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Express a displacement using base vectors

You know what a vector is, but writing one journey between two points in terms of a and b feels like guessing.

On this page
  1. How do you build a displacement step by step?
  2. Worked example
  3. The mistake to watch for
  4. Check yourself
  5. Where this leads next

To express a displacement, write the journey from one point to another as a sum of known vectors. The key rule is end minus start, or equivalently, walk along known legs and keep every sign.

This skill is the first step of every proof in two-dimensional vector proofs.

How do you build a displacement step by step?

  1. Name the start and end points of the displacement you want.
  2. Choose a route using vectors you know, often through the origin O.
  3. Write each leg. Going against a known vector gives its negative.
  4. Add the legs and simplify, collecting the coefficients of a and b.

For points A and B with →OA = a and →OB = b, going A to O to B gives −a + b, so →AB = b − a.

Worked example

In triangle OAB, →OA = a and →OB = b. P is the midpoint of OA and Q is the midpoint of OB.

Find →AB, →PQ and →PB. What do your answers show about PQ and AB?

→AB: route A to O to B: →AB = −a + b = b − a.

→PQ: route P to O to Q. Since P is the midpoint of OA, →PO = −½a. Since Q is the midpoint of OB, →OQ = ½b.

→PQ = −½a + ½b = ½(b − a)

→PB: route P to O to B: →PB = −½a + b = b − ½a.

Conclusion: →PQ = ½→AB, so PQ is parallel to AB and half its length.

The mistake to watch for

A common slip is to write →AB = a − b.

Mistaken answer: →AB = a − b

The student subtracted in the order the letters appear in the question, instead of end minus start.

To check, trace the journey with your finger: from A you must first go back to O, which is −a. Then you go out to B, which is +b.

So →AB = −a + b = b − a. A sketch with arrows on each leg catches this every time.

Check yourself

1. With →OA = a and →OB = b, write →BA.

Show answer

→BA = −→AB = −(b − a) = a − b. Check: B to O is −b, then O to A is +a.

a − b

2. OABC is a parallelogram with →OA = a and →OC = c. Write →OB and →AC.

Show answer

In a parallelogram →AB = →OC, so →OB = →OA + →AB = a + c. For →AC, go A to O to C: −a + c.

→OB = a + c, →AC = c − a

3. →OP = 3a − 2b and →OQ = a + 4b. Find →PQ.

Show answer

→PQ = →OQ − →OP = (a + 4b) − (3a − 2b) = a − 3a + 4b + 2b.

−2a + 6b

Where this leads next

Next, use displacements to place a point on a line in find a dividing point on a segment. The non-calculator working trainer is useful for the fraction work that comes with it.

If your diagrams are right but your first line keeps going wrong, our teachers look for exactly that in online one-to-one Additional Mathematics tuition.

Questions people ask

Is →AB equal to b − a or a − b?

If →OA = a and →OB = b, then →AB = b − a. Go from A back to O, which is −a, then from O to B, which is +b. The rule is end minus start, using position vectors measured from the same origin.

Can I choose any route from one point to another?

Yes. Any route along known vectors gives the same displacement, so choose the shortest route that uses only vectors you already know. Different routes produce the same final answer once simplified.

What are base vectors?

They are two non-parallel vectors, often a and b, used as building blocks. Every other vector in the diagram is written as a multiple of a plus a multiple of b, which makes comparisons between vectors possible.

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Your next step

If route-writing still feels uncertain once the diagram gets busy, a one-to-one teacher can watch your first line and correct the habit at the source.

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